ISMAGS Algorithm¶
ISMAGS Algorithm¶
Provides a Python implementation of the ISMAGS algorithm. 1
It is capable of finding (subgraph) isomorphisms between two graphs, taking the symmetry of the subgraph into account. In most cases the VF2 algorithm is faster (at least on small graphs) than this implementation, but in some cases there is an exponential number of isomorphisms that are symmetrically equivalent. In that case, the ISMAGS algorithm will provide only one solution per symmetry group.
>>> petersen = nx.petersen_graph()
>>> ismags = nx.isomorphism.ISMAGS(petersen, petersen)
>>> isomorphisms = list(ismags.isomorphisms_iter(symmetry=False))
>>> len(isomorphisms)
120
>>> isomorphisms = list(ismags.isomorphisms_iter(symmetry=True))
>>> answer = [{0: 0, 1: 1, 2: 2, 3: 3, 4: 4, 5: 5, 6: 6, 7: 7, 8: 8, 9: 9}]
>>> answer == isomorphisms
True
In addition, this implementation also provides an interface to find the
largest common induced subgraph 2 between any two graphs, again taking
symmetry into account. Given graph
and subgraph
the algorithm will remove
nodes from the subgraph
until subgraph
is isomorphic to a subgraph of
graph
. Since only the symmetry of subgraph
is taken into account it is
worth thinking about how you provide your graphs:
>>> graph1 = nx.path_graph(4)
>>> graph2 = nx.star_graph(3)
>>> ismags = nx.isomorphism.ISMAGS(graph1, graph2)
>>> ismags.is_isomorphic()
False
>>> largest_common_subgraph = list(ismags.largest_common_subgraph())
>>> answer = [{1: 0, 0: 1, 2: 2}, {2: 0, 1: 1, 3: 2}]
>>> answer == largest_common_subgraph
True
>>> ismags2 = nx.isomorphism.ISMAGS(graph2, graph1)
>>> largest_common_subgraph = list(ismags2.largest_common_subgraph())
>>> answer = [
... {1: 0, 0: 1, 2: 2},
... {1: 0, 0: 1, 3: 2},
... {2: 0, 0: 1, 1: 2},
... {2: 0, 0: 1, 3: 2},
... {3: 0, 0: 1, 1: 2},
... {3: 0, 0: 1, 2: 2},
... ]
>>> answer == largest_common_subgraph
True
However, when not taking symmetry into account, it doesn’t matter:
>>> largest_common_subgraph = list(ismags.largest_common_subgraph(symmetry=False))
>>> answer = [
... {1: 0, 0: 1, 2: 2},
... {1: 0, 2: 1, 0: 2},
... {2: 0, 1: 1, 3: 2},
... {2: 0, 3: 1, 1: 2},
... {1: 0, 0: 1, 2: 3},
... {1: 0, 2: 1, 0: 3},
... {2: 0, 1: 1, 3: 3},
... {2: 0, 3: 1, 1: 3},
... {1: 0, 0: 2, 2: 3},
... {1: 0, 2: 2, 0: 3},
... {2: 0, 1: 2, 3: 3},
... {2: 0, 3: 2, 1: 3},
... ]
>>> answer == largest_common_subgraph
True
>>> largest_common_subgraph = list(ismags2.largest_common_subgraph(symmetry=False))
>>> answer = [
... {1: 0, 0: 1, 2: 2},
... {1: 0, 0: 1, 3: 2},
... {2: 0, 0: 1, 1: 2},
... {2: 0, 0: 1, 3: 2},
... {3: 0, 0: 1, 1: 2},
... {3: 0, 0: 1, 2: 2},
... {1: 1, 0: 2, 2: 3},
... {1: 1, 0: 2, 3: 3},
... {2: 1, 0: 2, 1: 3},
... {2: 1, 0: 2, 3: 3},
... {3: 1, 0: 2, 1: 3},
... {3: 1, 0: 2, 2: 3},
... ]
>>> answer == largest_common_subgraph
True
Notes
The current implementation works for undirected graphs only. The algorithm in general should work for directed graphs as well though.
Node keys for both provided graphs need to be fully orderable as well as hashable.
Node and edge equality is assumed to be transitive: if A is equal to B, and B is equal to C, then A is equal to C.
References
 1
M. Houbraken, S. Demeyer, T. Michoel, P. Audenaert, D. Colle, M. Pickavet, “The IndexBased Subgraph Matching Algorithm with General Symmetries (ISMAGS): Exploiting Symmetry for Faster Subgraph Enumeration”, PLoS One 9(5): e97896, 2014. https://doi.org/10.1371/journal.pone.0097896
 2
https://en.wikipedia.org/wiki/Maximum_common_induced_subgraph
ISMAGS object¶

Implements the ISMAGS subgraph matching algorith. 

Find a minimal set of permutations and corresponding cosets that describe the symmetry of 

Returns True if 

Returns True if a subgraph of 

Does the same as 

Alternative name for 

Find the largest common induced subgraphs between 